michael hurd
Stalker be gone.
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Airflow requirement for a 350 cubic inch engine with a torque peak at 3000 rpm and a power peak at an engine speed of 5500 rpm.
Torque peak:
CFM = (350 x 3500) ÷ 3456 = 354 cfm at the torque peak
Power peak:
CFM = (350 x 5500) ÷ 3456 = 557 cfm at the power peak.
These are the engine’s theoretical air requirements if there was no restriction from throttle plates, manifold runners, intake ports, valves, exhaust.
In the above, this is the calculated airflow at wide open throttle based on 100% volumetric efficiency.
What is volumetric efficiency?
In short, the volumetric efficiency is a measure of the actual airflow through an engine vs. the theoretical airflow.
For a normal street engine, you can assume around 80% VE.
If measured on a dyno, the actual airflow through an engine at your torque peak ( 3000 rpm ) in the theoretical 350 engine is ~280 cfm, then the following equation would solve for VE.
VE% = 280/354 x 100 =79.09%
What about your power peak>? If you measured 417 cfm at your 5500 rpm power peak,
VE% = 417/557 x100 = 74.86%
Torque peak:
CFM = (350 x 3500) ÷ 3456 = 354 cfm at the torque peak
Power peak:
CFM = (350 x 5500) ÷ 3456 = 557 cfm at the power peak.
These are the engine’s theoretical air requirements if there was no restriction from throttle plates, manifold runners, intake ports, valves, exhaust.
In the above, this is the calculated airflow at wide open throttle based on 100% volumetric efficiency.
What is volumetric efficiency?
In short, the volumetric efficiency is a measure of the actual airflow through an engine vs. the theoretical airflow.
For a normal street engine, you can assume around 80% VE.
If measured on a dyno, the actual airflow through an engine at your torque peak ( 3000 rpm ) in the theoretical 350 engine is ~280 cfm, then the following equation would solve for VE.
VE% = 280/354 x 100 =79.09%
What about your power peak>? If you measured 417 cfm at your 5500 rpm power peak,
VE% = 417/557 x100 = 74.86%